员工轮班多个的组织需要安排足够的班次 为每天的班次带来的好处通常,时间表会有限制条件 例如“任何员工都应该连续工作两班”。查找 满足所有约束条件可能会很困难。
以下部分展示了员工调度问题的两个示例,以及 展示了如何使用 CP-SAT 求解器解题。
如需查看更复杂的示例,请参阅 轮班安排计划 。
护士调度问题
在下一个示例中,医院主管需要为四位患者 护士,但需满足以下条件:
- 每天分为三个班次,每个 8 小时。
- 每天,每个班次都分配给一名护士,没有任何护士工作的时间更长 调整一次。
- 在这三天的时间内,每位护士至少分配到两班。
以下部分介绍了护士调度问题的解决方案。
导入库
以下代码会导入所需的库。
Python
from ortools.sat.python import cp_model
C++
#include <stdlib.h> #include <atomic> #include <map> #include <numeric> #include <string> #include <tuple> #include <vector> #include "absl/strings/str_format.h" #include "ortools/base/logging.h" #include "ortools/sat/cp_model.h" #include "ortools/sat/cp_model.pb.h" #include "ortools/sat/cp_model_solver.h" #include "ortools/sat/model.h" #include "ortools/sat/sat_parameters.pb.h" #include "ortools/util/time_limit.h"
Java
import com.google.ortools.Loader; import com.google.ortools.sat.CpModel; import com.google.ortools.sat.CpSolver; import com.google.ortools.sat.CpSolverSolutionCallback; import com.google.ortools.sat.CpSolverStatus; import com.google.ortools.sat.LinearExpr; import com.google.ortools.sat.LinearExprBuilder; import com.google.ortools.sat.Literal; import java.util.ArrayList; import java.util.List; import java.util.stream.IntStream;
C#
using System; using System.Collections.Generic; using System.IO; using System.Linq; using Google.OrTools.Sat;
示例数据
以下代码将为示例创建数据。
Python
num_nurses = 4 num_shifts = 3 num_days = 3 all_nurses = range(num_nurses) all_shifts = range(num_shifts) all_days = range(num_days)
C++
const int num_nurses = 4; const int num_shifts = 3; const int num_days = 3; std::vector<int> all_nurses(num_nurses); std::iota(all_nurses.begin(), all_nurses.end(), 0); std::vector<int> all_shifts(num_shifts); std::iota(all_shifts.begin(), all_shifts.end(), 0); std::vector<int> all_days(num_days); std::iota(all_days.begin(), all_days.end(), 0);
Java
final int numNurses = 4; final int numDays = 3; final int numShifts = 3; final int[] allNurses = IntStream.range(0, numNurses).toArray(); final int[] allDays = IntStream.range(0, numDays).toArray(); final int[] allShifts = IntStream.range(0, numShifts).toArray();
C#
const int numNurses = 4; const int numDays = 3; const int numShifts = 3; int[] allNurses = Enumerable.Range(0, numNurses).ToArray(); int[] allDays = Enumerable.Range(0, numDays).ToArray(); int[] allShifts = Enumerable.Range(0, numShifts).ToArray();
创建模型
以下代码将创建模型。
Python
model = cp_model.CpModel()
C++
CpModelBuilder cp_model;
Java
CpModel model = new CpModel();
C#
CpModel model = new CpModel(); model.Model.Variables.Capacity = numNurses * numDays * numShifts;
创建变量
以下代码会创建一个变量数组。
Python
shifts = {} for n in all_nurses: for d in all_days: for s in all_shifts: shifts[(n, d, s)] = model.new_bool_var(f"shift_n{n}_d{d}_s{s}")
C++
std::map<std::tuple<int, int, int>, BoolVar> shifts; for (int n : all_nurses) { for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); shifts[key] = cp_model.NewBoolVar().WithName( absl::StrFormat("shift_n%dd%ds%d", n, d, s)); } } }
Java
Literal[][][] shifts = new Literal[numNurses][numDays][numShifts]; for (int n : allNurses) { for (int d : allDays) { for (int s : allShifts) { shifts[n][d][s] = model.newBoolVar("shifts_n" + n + "d" + d + "s" + s); } } }
C#
Dictionary<(int, int, int), BoolVar> shifts = new Dictionary<(int, int, int), BoolVar>(numNurses * numDays * numShifts); foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { shifts.Add((n, d, s), model.NewBoolVar($"shifts_n{n}d{d}s{s}")); } } }
该数组定义了护士轮班作业,如下所示:
如果在 d 天为护士 n 分配了班次 s,则 shifts[(n, d, s)]
等于 1,0 为 0
否则。
为护士分配轮班
接下来,我们展示如何根据以下限制条件分配护士班:
- 每个班次每天分配给一名护士。
- 每位护士每天最多工作一个班次。
以下是创建第一个条件的代码。
Python
for d in all_days: for s in all_shifts: model.add_exactly_one(shifts[(n, d, s)] for n in all_nurses)
C++
for (int d : all_days) { for (int s : all_shifts) { std::vector<BoolVar> nurses; for (int n : all_nurses) { auto key = std::make_tuple(n, d, s); nurses.push_back(shifts[key]); } cp_model.AddExactlyOne(nurses); } }
Java
for (int d : allDays) { for (int s : allShifts) { List<Literal> nurses = new ArrayList<>(); for (int n : allNurses) { nurses.add(shifts[n][d][s]); } model.addExactlyOne(nurses); } }
C#
List<ILiteral> literals = new List<ILiteral>(); foreach (int d in allDays) { foreach (int s in allShifts) { foreach (int n in allNurses) { literals.Add(shifts[(n, d, s)]); } model.AddExactlyOne(literals); literals.Clear(); } }
最后一行显示每个班次分配到该班次的护士人数总和 Shift 为 1。
接下来的代码要求每位护士每个班次最多 。
Python
for n in all_nurses: for d in all_days: model.add_at_most_one(shifts[(n, d, s)] for s in all_shifts)
C++
for (int n : all_nurses) { for (int d : all_days) { std::vector<BoolVar> work; for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); work.push_back(shifts[key]); } cp_model.AddAtMostOne(work); } }
Java
for (int n : allNurses) { for (int d : allDays) { List<Literal> work = new ArrayList<>(); for (int s : allShifts) { work.add(shifts[n][d][s]); } model.addAtMostOne(work); } }
C#
foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { literals.Add(shifts[(n, d, s)]); } model.AddAtMostOne(literals); literals.Clear(); } }
对于每位护士,分配给该护士的班次最多为 1 次(“最多” 因为护士可能可以请假)。
均匀分配班次
接下来,我们将展示如何尽可能均匀地为护士分配轮班。 由于这三天的时间段有 9 次调整,因此我们可以分配 2 次调整 四位护士 之后剩余 1 个班次,可以分配给任何护士。
以下代码可以确保每位护士在 。
Python
# Try to distribute the shifts evenly, so that each nurse works # min_shifts_per_nurse shifts. If this is not possible, because the total # number of shifts is not divisible by the number of nurses, some nurses will # be assigned one more shift. min_shifts_per_nurse = (num_shifts * num_days) // num_nurses if num_shifts * num_days % num_nurses == 0: max_shifts_per_nurse = min_shifts_per_nurse else: max_shifts_per_nurse = min_shifts_per_nurse + 1 for n in all_nurses: shifts_worked = [] for d in all_days: for s in all_shifts: shifts_worked.append(shifts[(n, d, s)]) model.add(min_shifts_per_nurse <= sum(shifts_worked)) model.add(sum(shifts_worked) <= max_shifts_per_nurse)
C++
// Try to distribute the shifts evenly, so that each nurse works // min_shifts_per_nurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int min_shifts_per_nurse = (num_shifts * num_days) / num_nurses; int max_shifts_per_nurse; if ((num_shifts * num_days) % num_nurses == 0) { max_shifts_per_nurse = min_shifts_per_nurse; } else { max_shifts_per_nurse = min_shifts_per_nurse + 1; } for (int n : all_nurses) { std::vector<BoolVar> shifts_worked; for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); shifts_worked.push_back(shifts[key]); } } cp_model.AddLessOrEqual(min_shifts_per_nurse, LinearExpr::Sum(shifts_worked)); cp_model.AddLessOrEqual(LinearExpr::Sum(shifts_worked), max_shifts_per_nurse); }
Java
// Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } for (int n : allNurses) { LinearExprBuilder shiftsWorked = LinearExpr.newBuilder(); for (int d : allDays) { for (int s : allShifts) { shiftsWorked.add(shifts[n][d][s]); } } model.addLinearConstraint(shiftsWorked, minShiftsPerNurse, maxShiftsPerNurse); }
C#
// Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } List<IntVar> shiftsWorked = new List<IntVar>(); foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { shiftsWorked.Add(shifts[(n, d, s)]); } } model.AddLinearConstraint(LinearExpr.Sum(shiftsWorked), minShiftsPerNurse, maxShiftsPerNurse); shiftsWorked.Clear(); }
由于此时间表时间段内总共调整了 num_shifts * num_days
次,因此您
可以分配至少(num_shifts * num_days) // num_nurses
每班护士的班次可能有所不同。(此处 //
是 Python
整数除法运算符,用于返回常商的底数。)
对于 num_nurses = 4
、num_shifts = 3
和 num_days = 3
的给定值,
表达式 min_shifts_per_nurse
的值为 (3 * 3 // 4) = 2
,所以
可以为每位护士至少分配两个班次。这是由
约束条件(此处为 Python 代码)
model.add(min_shifts_per_nurse <= sum(shifts_worked))
由于在三天内总共进行了九次调整,因此发生了一次 为每位护士分配两班后剩余班次。额外调整的时间范围 分配给任何护士。
最后一行(此处为 Python 代码)
model.add(sum(shifts_worked) <= max_shifts_per_nurse)
确保每位护士的轮班不止一次。
在本示例中,没有必要使用限制条件,因为只有一个额外的 Shift 键。但是,对于不同的参数值,可能会进行多次额外的偏移, 那么必须设置限制条件
更新求解器参数
在非优化模型中,您可以为所有解决方案启用搜索。
Python
solver = cp_model.CpSolver() solver.parameters.linearization_level = 0 # Enumerate all solutions. solver.parameters.enumerate_all_solutions = True
C++
Model model; SatParameters parameters; parameters.set_linearization_level(0); // Enumerate all solutions. parameters.set_enumerate_all_solutions(true); model.Add(NewSatParameters(parameters));
Java
CpSolver solver = new CpSolver(); solver.getParameters().setLinearizationLevel(0); // Tell the solver to enumerate all solutions. solver.getParameters().setEnumerateAllSolutions(true);
C#
CpSolver solver = new CpSolver(); // Tell the solver to enumerate all solutions. solver.StringParameters += "linearization_level:0 " + "enumerate_all_solutions:true ";
注册解决方案回调
您需要在求解器上注册一个回调,每次调用时都会调用该回调 解决方案。
Python
class NursesPartialSolutionPrinter(cp_model.CpSolverSolutionCallback): """Print intermediate solutions.""" def __init__(self, shifts, num_nurses, num_days, num_shifts, limit): cp_model.CpSolverSolutionCallback.__init__(self) self._shifts = shifts self._num_nurses = num_nurses self._num_days = num_days self._num_shifts = num_shifts self._solution_count = 0 self._solution_limit = limit def on_solution_callback(self): self._solution_count += 1 print(f"Solution {self._solution_count}") for d in range(self._num_days): print(f"Day {d}") for n in range(self._num_nurses): is_working = False for s in range(self._num_shifts): if self.value(self._shifts[(n, d, s)]): is_working = True print(f" Nurse {n} works shift {s}") if not is_working: print(f" Nurse {n} does not work") if self._solution_count >= self._solution_limit: print(f"Stop search after {self._solution_limit} solutions") self.stop_search() def solutionCount(self): return self._solution_count # Display the first five solutions. solution_limit = 5 solution_printer = NursesPartialSolutionPrinter( shifts, num_nurses, num_days, num_shifts, solution_limit )
C++
// Create an atomic Boolean that will be periodically checked by the limit. std::atomic<bool> stopped(false); model.GetOrCreate<TimeLimit>()->RegisterExternalBooleanAsLimit(&stopped); const int kSolutionLimit = 5; int num_solutions = 0; model.Add(NewFeasibleSolutionObserver([&](const CpSolverResponse& r) { LOG(INFO) << "Solution " << num_solutions; for (int d : all_days) { LOG(INFO) << "Day " << std::to_string(d); for (int n : all_nurses) { bool is_working = false; for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); if (SolutionIntegerValue(r, shifts[key])) { is_working = true; LOG(INFO) << " Nurse " << std::to_string(n) << " works shift " << std::to_string(s); } } if (!is_working) { LOG(INFO) << " Nurse " << std::to_string(n) << " does not work"; } } } num_solutions++; if (num_solutions >= kSolutionLimit) { stopped = true; LOG(INFO) << "Stop search after " << kSolutionLimit << " solutions."; } }));
Java
final int solutionLimit = 5; class VarArraySolutionPrinterWithLimit extends CpSolverSolutionCallback { public VarArraySolutionPrinterWithLimit( int[] allNurses, int[] allDays, int[] allShifts, Literal[][][] shifts, int limit) { solutionCount = 0; this.allNurses = allNurses; this.allDays = allDays; this.allShifts = allShifts; this.shifts = shifts; solutionLimit = limit; } @Override public void onSolutionCallback() { System.out.printf("Solution #%d:%n", solutionCount); for (int d : allDays) { System.out.printf("Day %d%n", d); for (int n : allNurses) { boolean isWorking = false; for (int s : allShifts) { if (booleanValue(shifts[n][d][s])) { isWorking = true; System.out.printf(" Nurse %d work shift %d%n", n, s); } } if (!isWorking) { System.out.printf(" Nurse %d does not work%n", n); } } } solutionCount++; if (solutionCount >= solutionLimit) { System.out.printf("Stop search after %d solutions%n", solutionLimit); stopSearch(); } } public int getSolutionCount() { return solutionCount; } private int solutionCount; private final int[] allNurses; private final int[] allDays; private final int[] allShifts; private final Literal[][][] shifts; private final int solutionLimit; } VarArraySolutionPrinterWithLimit cb = new VarArraySolutionPrinterWithLimit(allNurses, allDays, allShifts, shifts, solutionLimit);
C#
首先,定义 SolutionPrinter
类。
public class SolutionPrinter : CpSolverSolutionCallback { public SolutionPrinter(int[] allNurses, int[] allDays, int[] allShifts, Dictionary<(int, int, int), BoolVar> shifts, int limit) { solutionCount_ = 0; allNurses_ = allNurses; allDays_ = allDays; allShifts_ = allShifts; shifts_ = shifts; solutionLimit_ = limit; } public override void OnSolutionCallback() { Console.WriteLine($"Solution #{solutionCount_}:"); foreach (int d in allDays_) { Console.WriteLine($"Day {d}"); foreach (int n in allNurses_) { bool isWorking = false; foreach (int s in allShifts_) { if (Value(shifts_[(n, d, s)]) == 1L) { isWorking = true; Console.WriteLine($" Nurse {n} work shift {s}"); } } if (!isWorking) { Console.WriteLine($" Nurse {d} does not work"); } } } solutionCount_++; if (solutionCount_ >= solutionLimit_) { Console.WriteLine($"Stop search after {solutionLimit_} solutions"); StopSearch(); } } public int SolutionCount() { return solutionCount_; } private int solutionCount_; private int[] allNurses_; private int[] allDays_; private int[] allShifts_; private Dictionary<(int, int, int), BoolVar> shifts_; private int solutionLimit_; }然后使用以下代码对其进行实例化:
const int solutionLimit = 5; SolutionPrinter cb = new SolutionPrinter(allNurses, allDays, allShifts, shifts, solutionLimit);
调用求解器
以下代码会调用求解器,并显示前五个解。
Python
solver.solve(model, solution_printer)
C++
const CpSolverResponse response = SolveCpModel(cp_model.Build(), &model);
Java
CpSolverStatus status = solver.solve(model, cb); System.out.println("Status: " + status); System.out.println(cb.getSolutionCount() + " solutions found.");
C#
CpSolverStatus status = solver.Solve(model, cb); Console.WriteLine($"Solve status: {status}");
解决方案
以下是前五种解决方案。
Solution 0
Day 0
Nurse 0 does not work
Nurse 1 works shift 0
Nurse 2 works shift 1
Nurse 3 works shift 2
Day 1
Nurse 0 works shift 2
Nurse 1 does not work
Nurse 2 works shift 1
Nurse 3 works shift 0
Day 2
Nurse 0 works shift 2
Nurse 1 works shift 1
Nurse 2 works shift 0
Nurse 3 does not work
Solution 1
Day 0
Nurse 0 works shift 0
Nurse 1 does not work
Nurse 2 works shift 1
Nurse 3 works shift 2
Day 1
Nurse 0 does not work
Nurse 1 works shift 2
Nurse 2 works shift 1
Nurse 3 works shift 0
Day 2
Nurse 0 works shift 2
Nurse 1 works shift 1
Nurse 2 works shift 0
Nurse 3 does not work
Solution 2
Day 0 Nurse 0 works shift 0
Nurse 1 does not work
Nurse 2 works shift 1
Nurse 3 works shift 2
Day 1
Nurse 0 works shift 1
Nurse 1 works shift 2
Nurse 2 does not work
Nurse 3 works shift 0
Day 2
Nurse 0 works shift 2
Nurse 1 works shift 1
Nurse 2 works shift 0
Nurse 3 does not work
Solution 3
Day 0 Nurse 0 does not work
Nurse 1 works shift 0
Nurse 2 works shift 1
Nurse 3 works shift 2
Day 1
Nurse 0 works shift 1
Nurse 1 works shift 2
Nurse 2 does not work
Nurse 3 works shift 0
Day 2
Nurse 0 works shift 2
Nurse 1 works shift 1
Nurse 2 works shift 0
Nurse 3 does not work
Solution 4
Day 0
Nurse 0 does not work
Nurse 1 works shift 0
Nurse 2 works shift 1
Nurse 3 works shift 2
Day 1
Nurse 0 works shift 2
Nurse 1 works shift 1
Nurse 2 does not work
Nurse 3 works shift 0
Day 2
Nurse 0 works shift 2
Nurse 1 works shift 1
Nurse 2 works shift 0
Nurse 3 does not work
Statistics
- conflicts : 5
- branches : 142
- wall time : 0.002484 s
- solutions found: 5
解决方案的总数是 5184。 以下计数参数解释了原因。
首先,为加班的护士提供 4 个选项。 选择护士后,可以给护士分配 3 个班次 这 3 天中的每一天。 额外偏移为 4 · 33 = 108。 分配了此护士后,每天还有 2 个未分配的班次。
在其余三名护士中,其中一位在第 0 天和第 1 天工作,一位在第 0 天和第 2 天工作, 其中一位员工在第 1 天和第 2 天工作 共有 3 个!= 将护士分配到这些日子的 6 种方法,如 如下图所示。(这三名护士分别标记为 A、B 和 C, 分配给了他们轮班。)
Day 0 Day 1 Day 2
A B A C B C
A B B C A C
A C A B B C
A C B C A B
B C A B A C
B C A C A B
对于上图中的每一行,有 23 = 8 种可能的方式 将剩余班次分配给护士(每天两个班次)。 因此,可能的分配总数为 108·6·8 = 5184。
整个计划
以下是针对护士调度问题的完整程序。
Python
"""Example of a simple nurse scheduling problem.""" from ortools.sat.python import cp_model def main() -> None: # Data. num_nurses = 4 num_shifts = 3 num_days = 3 all_nurses = range(num_nurses) all_shifts = range(num_shifts) all_days = range(num_days) # Creates the model. model = cp_model.CpModel() # Creates shift variables. # shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. shifts = {} for n in all_nurses: for d in all_days: for s in all_shifts: shifts[(n, d, s)] = model.new_bool_var(f"shift_n{n}_d{d}_s{s}") # Each shift is assigned to exactly one nurse in the schedule period. for d in all_days: for s in all_shifts: model.add_exactly_one(shifts[(n, d, s)] for n in all_nurses) # Each nurse works at most one shift per day. for n in all_nurses: for d in all_days: model.add_at_most_one(shifts[(n, d, s)] for s in all_shifts) # Try to distribute the shifts evenly, so that each nurse works # min_shifts_per_nurse shifts. If this is not possible, because the total # number of shifts is not divisible by the number of nurses, some nurses will # be assigned one more shift. min_shifts_per_nurse = (num_shifts * num_days) // num_nurses if num_shifts * num_days % num_nurses == 0: max_shifts_per_nurse = min_shifts_per_nurse else: max_shifts_per_nurse = min_shifts_per_nurse + 1 for n in all_nurses: shifts_worked = [] for d in all_days: for s in all_shifts: shifts_worked.append(shifts[(n, d, s)]) model.add(min_shifts_per_nurse <= sum(shifts_worked)) model.add(sum(shifts_worked) <= max_shifts_per_nurse) # Creates the solver and solve. solver = cp_model.CpSolver() solver.parameters.linearization_level = 0 # Enumerate all solutions. solver.parameters.enumerate_all_solutions = True class NursesPartialSolutionPrinter(cp_model.CpSolverSolutionCallback): """Print intermediate solutions.""" def __init__(self, shifts, num_nurses, num_days, num_shifts, limit): cp_model.CpSolverSolutionCallback.__init__(self) self._shifts = shifts self._num_nurses = num_nurses self._num_days = num_days self._num_shifts = num_shifts self._solution_count = 0 self._solution_limit = limit def on_solution_callback(self): self._solution_count += 1 print(f"Solution {self._solution_count}") for d in range(self._num_days): print(f"Day {d}") for n in range(self._num_nurses): is_working = False for s in range(self._num_shifts): if self.value(self._shifts[(n, d, s)]): is_working = True print(f" Nurse {n} works shift {s}") if not is_working: print(f" Nurse {n} does not work") if self._solution_count >= self._solution_limit: print(f"Stop search after {self._solution_limit} solutions") self.stop_search() def solutionCount(self): return self._solution_count # Display the first five solutions. solution_limit = 5 solution_printer = NursesPartialSolutionPrinter( shifts, num_nurses, num_days, num_shifts, solution_limit ) solver.solve(model, solution_printer) # Statistics. print("\nStatistics") print(f" - conflicts : {solver.num_conflicts}") print(f" - branches : {solver.num_branches}") print(f" - wall time : {solver.wall_time} s") print(f" - solutions found: {solution_printer.solutionCount()}") if __name__ == "__main__": main()
C++
// Example of a simple nurse scheduling problem. #include <stdlib.h> #include <atomic> #include <map> #include <numeric> #include <string> #include <tuple> #include <vector> #include "absl/strings/str_format.h" #include "ortools/base/logging.h" #include "ortools/sat/cp_model.h" #include "ortools/sat/cp_model.pb.h" #include "ortools/sat/cp_model_solver.h" #include "ortools/sat/model.h" #include "ortools/sat/sat_parameters.pb.h" #include "ortools/util/time_limit.h" namespace operations_research { namespace sat { void NurseSat() { const int num_nurses = 4; const int num_shifts = 3; const int num_days = 3; std::vector<int> all_nurses(num_nurses); std::iota(all_nurses.begin(), all_nurses.end(), 0); std::vector<int> all_shifts(num_shifts); std::iota(all_shifts.begin(), all_shifts.end(), 0); std::vector<int> all_days(num_days); std::iota(all_days.begin(), all_days.end(), 0); // Creates the model. CpModelBuilder cp_model; // Creates shift variables. // shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. std::map<std::tuple<int, int, int>, BoolVar> shifts; for (int n : all_nurses) { for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); shifts[key] = cp_model.NewBoolVar().WithName( absl::StrFormat("shift_n%dd%ds%d", n, d, s)); } } } // Each shift is assigned to exactly one nurse in the schedule period. for (int d : all_days) { for (int s : all_shifts) { std::vector<BoolVar> nurses; for (int n : all_nurses) { auto key = std::make_tuple(n, d, s); nurses.push_back(shifts[key]); } cp_model.AddExactlyOne(nurses); } } // Each nurse works at most one shift per day. for (int n : all_nurses) { for (int d : all_days) { std::vector<BoolVar> work; for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); work.push_back(shifts[key]); } cp_model.AddAtMostOne(work); } } // Try to distribute the shifts evenly, so that each nurse works // min_shifts_per_nurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int min_shifts_per_nurse = (num_shifts * num_days) / num_nurses; int max_shifts_per_nurse; if ((num_shifts * num_days) % num_nurses == 0) { max_shifts_per_nurse = min_shifts_per_nurse; } else { max_shifts_per_nurse = min_shifts_per_nurse + 1; } for (int n : all_nurses) { std::vector<BoolVar> shifts_worked; for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); shifts_worked.push_back(shifts[key]); } } cp_model.AddLessOrEqual(min_shifts_per_nurse, LinearExpr::Sum(shifts_worked)); cp_model.AddLessOrEqual(LinearExpr::Sum(shifts_worked), max_shifts_per_nurse); } Model model; SatParameters parameters; parameters.set_linearization_level(0); // Enumerate all solutions. parameters.set_enumerate_all_solutions(true); model.Add(NewSatParameters(parameters)); // Display the first five solutions. // Create an atomic Boolean that will be periodically checked by the limit. std::atomic<bool> stopped(false); model.GetOrCreate<TimeLimit>()->RegisterExternalBooleanAsLimit(&stopped); const int kSolutionLimit = 5; int num_solutions = 0; model.Add(NewFeasibleSolutionObserver([&](const CpSolverResponse& r) { LOG(INFO) << "Solution " << num_solutions; for (int d : all_days) { LOG(INFO) << "Day " << std::to_string(d); for (int n : all_nurses) { bool is_working = false; for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); if (SolutionIntegerValue(r, shifts[key])) { is_working = true; LOG(INFO) << " Nurse " << std::to_string(n) << " works shift " << std::to_string(s); } } if (!is_working) { LOG(INFO) << " Nurse " << std::to_string(n) << " does not work"; } } } num_solutions++; if (num_solutions >= kSolutionLimit) { stopped = true; LOG(INFO) << "Stop search after " << kSolutionLimit << " solutions."; } })); const CpSolverResponse response = SolveCpModel(cp_model.Build(), &model); // Statistics. LOG(INFO) << "Statistics"; LOG(INFO) << CpSolverResponseStats(response); LOG(INFO) << "solutions found : " << std::to_string(num_solutions); } } // namespace sat } // namespace operations_research int main() { operations_research::sat::NurseSat(); return EXIT_SUCCESS; }
Java
package com.google.ortools.sat.samples; import com.google.ortools.Loader; import com.google.ortools.sat.CpModel; import com.google.ortools.sat.CpSolver; import com.google.ortools.sat.CpSolverSolutionCallback; import com.google.ortools.sat.CpSolverStatus; import com.google.ortools.sat.LinearExpr; import com.google.ortools.sat.LinearExprBuilder; import com.google.ortools.sat.Literal; import java.util.ArrayList; import java.util.List; import java.util.stream.IntStream; /** Nurses problem. */ public class NursesSat { public static void main(String[] args) { Loader.loadNativeLibraries(); final int numNurses = 4; final int numDays = 3; final int numShifts = 3; final int[] allNurses = IntStream.range(0, numNurses).toArray(); final int[] allDays = IntStream.range(0, numDays).toArray(); final int[] allShifts = IntStream.range(0, numShifts).toArray(); // Creates the model. CpModel model = new CpModel(); // Creates shift variables. // shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. Literal[][][] shifts = new Literal[numNurses][numDays][numShifts]; for (int n : allNurses) { for (int d : allDays) { for (int s : allShifts) { shifts[n][d][s] = model.newBoolVar("shifts_n" + n + "d" + d + "s" + s); } } } // Each shift is assigned to exactly one nurse in the schedule period. for (int d : allDays) { for (int s : allShifts) { List<Literal> nurses = new ArrayList<>(); for (int n : allNurses) { nurses.add(shifts[n][d][s]); } model.addExactlyOne(nurses); } } // Each nurse works at most one shift per day. for (int n : allNurses) { for (int d : allDays) { List<Literal> work = new ArrayList<>(); for (int s : allShifts) { work.add(shifts[n][d][s]); } model.addAtMostOne(work); } } // Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } for (int n : allNurses) { LinearExprBuilder shiftsWorked = LinearExpr.newBuilder(); for (int d : allDays) { for (int s : allShifts) { shiftsWorked.add(shifts[n][d][s]); } } model.addLinearConstraint(shiftsWorked, minShiftsPerNurse, maxShiftsPerNurse); } CpSolver solver = new CpSolver(); solver.getParameters().setLinearizationLevel(0); // Tell the solver to enumerate all solutions. solver.getParameters().setEnumerateAllSolutions(true); // Display the first five solutions. final int solutionLimit = 5; class VarArraySolutionPrinterWithLimit extends CpSolverSolutionCallback { public VarArraySolutionPrinterWithLimit( int[] allNurses, int[] allDays, int[] allShifts, Literal[][][] shifts, int limit) { solutionCount = 0; this.allNurses = allNurses; this.allDays = allDays; this.allShifts = allShifts; this.shifts = shifts; solutionLimit = limit; } @Override public void onSolutionCallback() { System.out.printf("Solution #%d:%n", solutionCount); for (int d : allDays) { System.out.printf("Day %d%n", d); for (int n : allNurses) { boolean isWorking = false; for (int s : allShifts) { if (booleanValue(shifts[n][d][s])) { isWorking = true; System.out.printf(" Nurse %d work shift %d%n", n, s); } } if (!isWorking) { System.out.printf(" Nurse %d does not work%n", n); } } } solutionCount++; if (solutionCount >= solutionLimit) { System.out.printf("Stop search after %d solutions%n", solutionLimit); stopSearch(); } } public int getSolutionCount() { return solutionCount; } private int solutionCount; private final int[] allNurses; private final int[] allDays; private final int[] allShifts; private final Literal[][][] shifts; private final int solutionLimit; } VarArraySolutionPrinterWithLimit cb = new VarArraySolutionPrinterWithLimit(allNurses, allDays, allShifts, shifts, solutionLimit); // Creates a solver and solves the model. CpSolverStatus status = solver.solve(model, cb); System.out.println("Status: " + status); System.out.println(cb.getSolutionCount() + " solutions found."); // Statistics. System.out.println("Statistics"); System.out.printf(" conflicts: %d%n", solver.numConflicts()); System.out.printf(" branches : %d%n", solver.numBranches()); System.out.printf(" wall time: %f s%n", solver.wallTime()); } private NursesSat() {} }
C#
using System; using System.Collections.Generic; using System.IO; using System.Linq; using Google.OrTools.Sat; public class NursesSat { public class SolutionPrinter : CpSolverSolutionCallback { public SolutionPrinter(int[] allNurses, int[] allDays, int[] allShifts, Dictionary<(int, int, int), BoolVar> shifts, int limit) { solutionCount_ = 0; allNurses_ = allNurses; allDays_ = allDays; allShifts_ = allShifts; shifts_ = shifts; solutionLimit_ = limit; } public override void OnSolutionCallback() { Console.WriteLine($"Solution #{solutionCount_}:"); foreach (int d in allDays_) { Console.WriteLine($"Day {d}"); foreach (int n in allNurses_) { bool isWorking = false; foreach (int s in allShifts_) { if (Value(shifts_[(n, d, s)]) == 1L) { isWorking = true; Console.WriteLine($" Nurse {n} work shift {s}"); } } if (!isWorking) { Console.WriteLine($" Nurse {d} does not work"); } } } solutionCount_++; if (solutionCount_ >= solutionLimit_) { Console.WriteLine($"Stop search after {solutionLimit_} solutions"); StopSearch(); } } public int SolutionCount() { return solutionCount_; } private int solutionCount_; private int[] allNurses_; private int[] allDays_; private int[] allShifts_; private Dictionary<(int, int, int), BoolVar> shifts_; private int solutionLimit_; } public static void Main(String[] args) { const int numNurses = 4; const int numDays = 3; const int numShifts = 3; int[] allNurses = Enumerable.Range(0, numNurses).ToArray(); int[] allDays = Enumerable.Range(0, numDays).ToArray(); int[] allShifts = Enumerable.Range(0, numShifts).ToArray(); // Creates the model. CpModel model = new CpModel(); model.Model.Variables.Capacity = numNurses * numDays * numShifts; // Creates shift variables. // shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. Dictionary<(int, int, int), BoolVar> shifts = new Dictionary<(int, int, int), BoolVar>(numNurses * numDays * numShifts); foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { shifts.Add((n, d, s), model.NewBoolVar($"shifts_n{n}d{d}s{s}")); } } } // Each shift is assigned to exactly one nurse in the schedule period. List<ILiteral> literals = new List<ILiteral>(); foreach (int d in allDays) { foreach (int s in allShifts) { foreach (int n in allNurses) { literals.Add(shifts[(n, d, s)]); } model.AddExactlyOne(literals); literals.Clear(); } } // Each nurse works at most one shift per day. foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { literals.Add(shifts[(n, d, s)]); } model.AddAtMostOne(literals); literals.Clear(); } } // Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } List<IntVar> shiftsWorked = new List<IntVar>(); foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { shiftsWorked.Add(shifts[(n, d, s)]); } } model.AddLinearConstraint(LinearExpr.Sum(shiftsWorked), minShiftsPerNurse, maxShiftsPerNurse); shiftsWorked.Clear(); } CpSolver solver = new CpSolver(); // Tell the solver to enumerate all solutions. solver.StringParameters += "linearization_level:0 " + "enumerate_all_solutions:true "; // Display the first five solutions. const int solutionLimit = 5; SolutionPrinter cb = new SolutionPrinter(allNurses, allDays, allShifts, shifts, solutionLimit); // Solve CpSolverStatus status = solver.Solve(model, cb); Console.WriteLine($"Solve status: {status}"); Console.WriteLine("Statistics"); Console.WriteLine($" conflicts: {solver.NumConflicts()}"); Console.WriteLine($" branches : {solver.NumBranches()}"); Console.WriteLine($" wall time: {solver.WallTime()}s"); } }
通过轮班申请安排
在本节中,我们以上一个示例为 添加 特定的转变。 然后,我们会寻找一个能最大限度地增加所满足请求数量的时间表。 对于大多数调度问题,最好优化目标函数,因为它 通常,打印所有可能的时间表并不现实。
此示例与上一个示例具有相同的约束条件。
导入库
以下代码会导入所需的库。
Python
from typing import Union from ortools.sat.python import cp_model
C++
#include <stdlib.h> #include <cstdint> #include <map> #include <numeric> #include <string> #include <tuple> #include <vector> #include "absl/strings/str_format.h" #include "ortools/base/logging.h" #include "ortools/sat/cp_model.h" #include "ortools/sat/cp_model.pb.h" #include "ortools/sat/cp_model_solver.h"
Java
import com.google.ortools.Loader; import com.google.ortools.sat.CpModel; import com.google.ortools.sat.CpSolver; import com.google.ortools.sat.CpSolverStatus; import com.google.ortools.sat.LinearExpr; import com.google.ortools.sat.LinearExprBuilder; import com.google.ortools.sat.Literal; import java.util.ArrayList; import java.util.List; import java.util.stream.IntStream;
C#
using System; using System.Collections.Generic; using System.Linq; using Google.OrTools.Sat;
示例数据
之后显示此示例的数据。
Python
num_nurses = 5 num_shifts = 3 num_days = 7 all_nurses = range(num_nurses) all_shifts = range(num_shifts) all_days = range(num_days) shift_requests = [ [[0, 0, 1], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 1], [0, 1, 0], [0, 0, 1]], [[0, 0, 0], [0, 0, 0], [0, 1, 0], [0, 1, 0], [1, 0, 0], [0, 0, 0], [0, 0, 1]], [[0, 1, 0], [0, 1, 0], [0, 0, 0], [1, 0, 0], [0, 0, 0], [0, 1, 0], [0, 0, 0]], [[0, 0, 1], [0, 0, 0], [1, 0, 0], [0, 1, 0], [0, 0, 0], [1, 0, 0], [0, 0, 0]], [[0, 0, 0], [0, 0, 1], [0, 1, 0], [0, 0, 0], [1, 0, 0], [0, 1, 0], [0, 0, 0]], ]
C++
const int num_nurses = 5; const int num_days = 7; const int num_shifts = 3; std::vector<int> all_nurses(num_nurses); std::iota(all_nurses.begin(), all_nurses.end(), 0); std::vector<int> all_days(num_days); std::iota(all_days.begin(), all_days.end(), 0); std::vector<int> all_shifts(num_shifts); std::iota(all_shifts.begin(), all_shifts.end(), 0); std::vector<std::vector<std::vector<int64_t>>> shift_requests = { { {0, 0, 1}, {0, 0, 0}, {0, 0, 0}, {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 1}, }, { {0, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 1, 0}, {1, 0, 0}, {0, 0, 0}, {0, 0, 1}, }, { {0, 1, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, { {0, 0, 1}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, }, { {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, };
Java
final int numNurses = 5; final int numDays = 7; final int numShifts = 3; final int[] allNurses = IntStream.range(0, numNurses).toArray(); final int[] allDays = IntStream.range(0, numDays).toArray(); final int[] allShifts = IntStream.range(0, numShifts).toArray(); final int[][][] shiftRequests = new int[][][] { { {0, 0, 1}, {0, 0, 0}, {0, 0, 0}, {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 1}, }, { {0, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 1, 0}, {1, 0, 0}, {0, 0, 0}, {0, 0, 1}, }, { {0, 1, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, { {0, 0, 1}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, }, { {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, };
C#
const int numNurses = 5; const int numDays = 7; const int numShifts = 3; int[] allNurses = Enumerable.Range(0, numNurses).ToArray(); int[] allDays = Enumerable.Range(0, numDays).ToArray(); int[] allShifts = Enumerable.Range(0, numShifts).ToArray(); int[,,] shiftRequests = new int[,,] { { { 0, 0, 1 }, { 0, 0, 0 }, { 0, 0, 0 }, { 0, 0, 0 }, { 0, 0, 1 }, { 0, 1, 0 }, { 0, 0, 1 }, }, { { 0, 0, 0 }, { 0, 0, 0 }, { 0, 1, 0 }, { 0, 1, 0 }, { 1, 0, 0 }, { 0, 0, 0 }, { 0, 0, 1 }, }, { { 0, 1, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, }, { { 0, 0, 1 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 0, 0 }, }, { { 0, 0, 0 }, { 0, 0, 1 }, { 0, 1, 0 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, }, };
创建模型
以下代码将创建模型。
Python
model = cp_model.CpModel()
C++
CpModelBuilder cp_model;
Java
CpModel model = new CpModel();
C#
CpModel model = new CpModel();
创建变量
以下代码是问题的变量数组。
除上例中的变量外,该数据还包含 一组三元组,对应于每天三次的班次。每个 thirdle 为 0 或 1,表示是否请求了偏移。例如, 第 1 行第五个位置中的三个数字 [0, 0, 1] 表示护士 1 要求 在第 5 天调整 3。
Python
shifts = {} for n in all_nurses: for d in all_days: for s in all_shifts: shifts[(n, d, s)] = model.new_bool_var(f"shift_n{n}_d{d}_s{s}")
C++
std::map<std::tuple<int, int, int>, BoolVar> shifts; for (int n : all_nurses) { for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); shifts[key] = cp_model.NewBoolVar().WithName( absl::StrFormat("shift_n%dd%ds%d", n, d, s)); } } }
Java
Literal[][][] shifts = new Literal[numNurses][numDays][numShifts]; for (int n : allNurses) { for (int d : allDays) { for (int s : allShifts) { shifts[n][d][s] = model.newBoolVar("shifts_n" + n + "d" + d + "s" + s); } } }
C#
Dictionary<Tuple<int, int, int>, IntVar> shifts = new Dictionary<Tuple<int, int, int>, IntVar>(); foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { shifts.Add(Tuple.Create(n, d, s), model.NewBoolVar($"shifts_n{n}d{d}s{s}")); } } }
创建限制条件
以下代码为问题创建约束条件。
Python
for d in all_days: for s in all_shifts: model.add_exactly_one(shifts[(n, d, s)] for n in all_nurses)
C++
for (int d : all_days) { for (int s : all_shifts) { std::vector<BoolVar> nurses; for (int n : all_nurses) { auto key = std::make_tuple(n, d, s); nurses.push_back(shifts[key]); } cp_model.AddExactlyOne(nurses); } }
Java
for (int d : allDays) { for (int s : allShifts) { List<Literal> nurses = new ArrayList<>(); for (int n : allNurses) { nurses.add(shifts[n][d][s]); } model.addExactlyOne(nurses); } }
C#
foreach (int d in allDays) { foreach (int s in allShifts) { IntVar[] x = new IntVar[numNurses]; foreach (int n in allNurses) { var key = Tuple.Create(n, d, s); x[n] = shifts[key]; } model.Add(LinearExpr.Sum(x) == 1); } }
Python
for n in all_nurses: for d in all_days: model.add_at_most_one(shifts[(n, d, s)] for s in all_shifts)
C++
for (int n : all_nurses) { for (int d : all_days) { std::vector<BoolVar> work; for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); work.push_back(shifts[key]); } cp_model.AddAtMostOne(work); } }
Java
for (int n : allNurses) { for (int d : allDays) { List<Literal> work = new ArrayList<>(); for (int s : allShifts) { work.add(shifts[n][d][s]); } model.addAtMostOne(work); } }
C#
foreach (int n in allNurses) { foreach (int d in allDays) { IntVar[] x = new IntVar[numShifts]; foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); x[s] = shifts[key]; } model.Add(LinearExpr.Sum(x) <= 1); } }
Python
# Try to distribute the shifts evenly, so that each nurse works # min_shifts_per_nurse shifts. If this is not possible, because the total # number of shifts is not divisible by the number of nurses, some nurses will # be assigned one more shift. min_shifts_per_nurse = (num_shifts * num_days) // num_nurses if num_shifts * num_days % num_nurses == 0: max_shifts_per_nurse = min_shifts_per_nurse else: max_shifts_per_nurse = min_shifts_per_nurse + 1 for n in all_nurses: num_shifts_worked: Union[cp_model.LinearExpr, int] = 0 for d in all_days: for s in all_shifts: num_shifts_worked += shifts[(n, d, s)] model.add(min_shifts_per_nurse <= num_shifts_worked) model.add(num_shifts_worked <= max_shifts_per_nurse)
C++
// Try to distribute the shifts evenly, so that each nurse works // min_shifts_per_nurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int min_shifts_per_nurse = (num_shifts * num_days) / num_nurses; int max_shifts_per_nurse; if ((num_shifts * num_days) % num_nurses == 0) { max_shifts_per_nurse = min_shifts_per_nurse; } else { max_shifts_per_nurse = min_shifts_per_nurse + 1; } for (int n : all_nurses) { LinearExpr num_worked_shifts; for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); num_worked_shifts += shifts[key]; } } cp_model.AddLessOrEqual(min_shifts_per_nurse, num_worked_shifts); cp_model.AddLessOrEqual(num_worked_shifts, max_shifts_per_nurse); }
Java
// Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } for (int n : allNurses) { LinearExprBuilder numShiftsWorked = LinearExpr.newBuilder(); for (int d : allDays) { for (int s : allShifts) { numShiftsWorked.add(shifts[n][d][s]); } } model.addLinearConstraint(numShiftsWorked, minShiftsPerNurse, maxShiftsPerNurse); }
C#
// Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } foreach (int n in allNurses) { IntVar[] numShiftsWorked = new IntVar[numDays * numShifts]; foreach (int d in allDays) { foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); numShiftsWorked[d * numShifts + s] = shifts[key]; } } model.AddLinearConstraint(LinearExpr.Sum(numShiftsWorked), minShiftsPerNurse, maxShiftsPerNurse); }
示例的目标
我们希望优化以下目标函数。
Python
model.maximize( sum( shift_requests[n][d][s] * shifts[(n, d, s)] for n in all_nurses for d in all_days for s in all_shifts ) )
C++
LinearExpr objective_expr; for (int n : all_nurses) { for (int d : all_days) { for (int s : all_shifts) { if (shift_requests[n][d][s] == 1) { auto key = std::make_tuple(n, d, s); objective_expr += shifts[key] * shift_requests[n][d][s]; } } } } cp_model.Maximize(objective_expr);
Java
LinearExprBuilder obj = LinearExpr.newBuilder(); for (int n : allNurses) { for (int d : allDays) { for (int s : allShifts) { obj.addTerm(shifts[n][d][s], shiftRequests[n][d][s]); } } } model.maximize(obj);
C#
IntVar[] flatShifts = new IntVar[numNurses * numDays * numShifts]; int[] flatShiftRequests = new int[numNurses * numDays * numShifts]; foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); flatShifts[n * numDays * numShifts + d * numShifts + s] = shifts[key]; flatShiftRequests[n * numDays * numShifts + d * numShifts + s] = shiftRequests[n, d, s]; } } } model.Maximize(LinearExpr.WeightedSum(flatShifts, flatShiftRequests));
由于 shift_requests[n][d][s] * shifts[(n, d, s)
为 1,如果分配了班次 s
在第 d
天照顾n
,并且该护士要求轮班(否则为 0),
目标是调整满足请求的分配数量。
调用求解器
以下代码会调用求解器。
Python
solver = cp_model.CpSolver() status = solver.solve(model)
C++
const CpSolverResponse response = Solve(cp_model.Build());
Java
CpSolver solver = new CpSolver(); CpSolverStatus status = solver.solve(model);
C#
CpSolver solver = new CpSolver(); CpSolverStatus status = solver.Solve(model); Console.WriteLine($"Solve status: {status}");
显示结果
以下代码显示了以下输出,其中包含了 时间表(虽然可能不是唯一的)。输出会显示 请求的数量以及满足的请求数量。
Python
if status == cp_model.OPTIMAL: print("Solution:") for d in all_days: print("Day", d) for n in all_nurses: for s in all_shifts: if solver.value(shifts[(n, d, s)]) == 1: if shift_requests[n][d][s] == 1: print("Nurse", n, "works shift", s, "(requested).") else: print("Nurse", n, "works shift", s, "(not requested).") print() print( f"Number of shift requests met = {solver.objective_value}", f"(out of {num_nurses * min_shifts_per_nurse})", ) else: print("No optimal solution found !")
C++
if (response.status() == CpSolverStatus::OPTIMAL) { LOG(INFO) << "Solution:"; for (int d : all_days) { LOG(INFO) << "Day " << std::to_string(d); for (int n : all_nurses) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); if (SolutionIntegerValue(response, shifts[key]) == 1) { if (shift_requests[n][d][s] == 1) { LOG(INFO) << " Nurse " << std::to_string(n) << " works shift " << std::to_string(s) << " (requested)."; } else { LOG(INFO) << " Nurse " << std::to_string(n) << " works shift " << std::to_string(s) << " (not requested)."; } } } } LOG(INFO) << ""; } LOG(INFO) << "Number of shift requests met = " << response.objective_value() << " (out of " << num_nurses * min_shifts_per_nurse << ")"; } else { LOG(INFO) << "No optimal solution found !"; }
Java
if (status == CpSolverStatus.OPTIMAL || status == CpSolverStatus.FEASIBLE) { System.out.printf("Solution:%n"); for (int d : allDays) { System.out.printf("Day %d%n", d); for (int n : allNurses) { for (int s : allShifts) { if (solver.booleanValue(shifts[n][d][s])) { if (shiftRequests[n][d][s] == 1) { System.out.printf(" Nurse %d works shift %d (requested).%n", n, s); } else { System.out.printf(" Nurse %d works shift %d (not requested).%n", n, s); } } } } } System.out.printf("Number of shift requests met = %f (out of %d)%n", solver.objectiveValue(), numNurses * minShiftsPerNurse); } else { System.out.printf("No optimal solution found !"); }
C#
if (status == CpSolverStatus.Optimal || status == CpSolverStatus.Feasible) { Console.WriteLine("Solution:"); foreach (int d in allDays) { Console.WriteLine($"Day {d}"); foreach (int n in allNurses) { bool isWorking = false; foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); if (solver.Value(shifts[key]) == 1L) { if (shiftRequests[n, d, s] == 1) { Console.WriteLine($" Nurse {n} work shift {s} (requested)."); } else { Console.WriteLine($" Nurse {n} work shift {s} (not requested)."); } } } } } Console.WriteLine( $"Number of shift requests met = {solver.ObjectiveValue} (out of {numNurses * minShiftsPerNurse})."); } else { Console.WriteLine("No solution found."); }
运行该程序后,它会显示以下输出:
Day 0
Nurse 1 works shift 0 (not requested).
Nurse 2 works shift 1 (requested).
Nurse 3 works shift 2 (requested).
Day 1
Nurse 0 works shift 0 (not requested).
Nurse 2 works shift 1 (requested).
Nurse 4 works shift 2 (requested).
Day 2
Nurse 1 works shift 2 (not requested).
Nurse 3 works shift 0 (requested).
Nurse 4 works shift 1 (requested).
Day 3
Nurse 2 works shift 0 (requested).
Nurse 3 works shift 1 (requested).
Nurse 4 works shift 2 (not requested).
Day 4
Nurse 0 works shift 2 (requested).
Nurse 1 works shift 0 (requested).
Nurse 4 works shift 1 (not requested).
Day 5
Nurse 0 works shift 2 (not requested).
Nurse 2 works shift 1 (requested).
Nurse 3 works shift 0 (requested).
Day 6
Nurse 0 works shift 1 (not requested).
Nurse 1 works shift 2 (requested).
Nurse 4 works shift 0 (not requested).
Statistics
- Number of shift requests met = 13 (out of 20 )
- wall time : 0.003571 s
整个计划
以下是针对轮班请求安排的完整程序。
Python
"""Nurse scheduling problem with shift requests.""" from typing import Union from ortools.sat.python import cp_model def main() -> None: # This program tries to find an optimal assignment of nurses to shifts # (3 shifts per day, for 7 days), subject to some constraints (see below). # Each nurse can request to be assigned to specific shifts. # The optimal assignment maximizes the number of fulfilled shift requests. num_nurses = 5 num_shifts = 3 num_days = 7 all_nurses = range(num_nurses) all_shifts = range(num_shifts) all_days = range(num_days) shift_requests = [ [[0, 0, 1], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 1], [0, 1, 0], [0, 0, 1]], [[0, 0, 0], [0, 0, 0], [0, 1, 0], [0, 1, 0], [1, 0, 0], [0, 0, 0], [0, 0, 1]], [[0, 1, 0], [0, 1, 0], [0, 0, 0], [1, 0, 0], [0, 0, 0], [0, 1, 0], [0, 0, 0]], [[0, 0, 1], [0, 0, 0], [1, 0, 0], [0, 1, 0], [0, 0, 0], [1, 0, 0], [0, 0, 0]], [[0, 0, 0], [0, 0, 1], [0, 1, 0], [0, 0, 0], [1, 0, 0], [0, 1, 0], [0, 0, 0]], ] # Creates the model. model = cp_model.CpModel() # Creates shift variables. # shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. shifts = {} for n in all_nurses: for d in all_days: for s in all_shifts: shifts[(n, d, s)] = model.new_bool_var(f"shift_n{n}_d{d}_s{s}") # Each shift is assigned to exactly one nurse in . for d in all_days: for s in all_shifts: model.add_exactly_one(shifts[(n, d, s)] for n in all_nurses) # Each nurse works at most one shift per day. for n in all_nurses: for d in all_days: model.add_at_most_one(shifts[(n, d, s)] for s in all_shifts) # Try to distribute the shifts evenly, so that each nurse works # min_shifts_per_nurse shifts. If this is not possible, because the total # number of shifts is not divisible by the number of nurses, some nurses will # be assigned one more shift. min_shifts_per_nurse = (num_shifts * num_days) // num_nurses if num_shifts * num_days % num_nurses == 0: max_shifts_per_nurse = min_shifts_per_nurse else: max_shifts_per_nurse = min_shifts_per_nurse + 1 for n in all_nurses: num_shifts_worked: Union[cp_model.LinearExpr, int] = 0 for d in all_days: for s in all_shifts: num_shifts_worked += shifts[(n, d, s)] model.add(min_shifts_per_nurse <= num_shifts_worked) model.add(num_shifts_worked <= max_shifts_per_nurse) model.maximize( sum( shift_requests[n][d][s] * shifts[(n, d, s)] for n in all_nurses for d in all_days for s in all_shifts ) ) # Creates the solver and solve. solver = cp_model.CpSolver() status = solver.solve(model) if status == cp_model.OPTIMAL: print("Solution:") for d in all_days: print("Day", d) for n in all_nurses: for s in all_shifts: if solver.value(shifts[(n, d, s)]) == 1: if shift_requests[n][d][s] == 1: print("Nurse", n, "works shift", s, "(requested).") else: print("Nurse", n, "works shift", s, "(not requested).") print() print( f"Number of shift requests met = {solver.objective_value}", f"(out of {num_nurses * min_shifts_per_nurse})", ) else: print("No optimal solution found !") # Statistics. print("\nStatistics") print(f" - conflicts: {solver.num_conflicts}") print(f" - branches : {solver.num_branches}") print(f" - wall time: {solver.wall_time}s") if __name__ == "__main__": main()
C++
// Nurse scheduling problem with shift requests. #include <stdlib.h> #include <cstdint> #include <map> #include <numeric> #include <string> #include <tuple> #include <vector> #include "absl/strings/str_format.h" #include "ortools/base/logging.h" #include "ortools/sat/cp_model.h" #include "ortools/sat/cp_model.pb.h" #include "ortools/sat/cp_model_solver.h" namespace operations_research { namespace sat { void ScheduleRequestsSat() { const int num_nurses = 5; const int num_days = 7; const int num_shifts = 3; std::vector<int> all_nurses(num_nurses); std::iota(all_nurses.begin(), all_nurses.end(), 0); std::vector<int> all_days(num_days); std::iota(all_days.begin(), all_days.end(), 0); std::vector<int> all_shifts(num_shifts); std::iota(all_shifts.begin(), all_shifts.end(), 0); std::vector<std::vector<std::vector<int64_t>>> shift_requests = { { {0, 0, 1}, {0, 0, 0}, {0, 0, 0}, {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 1}, }, { {0, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 1, 0}, {1, 0, 0}, {0, 0, 0}, {0, 0, 1}, }, { {0, 1, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, { {0, 0, 1}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, }, { {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, }; // Creates the model. CpModelBuilder cp_model; // Creates shift variables. // shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. std::map<std::tuple<int, int, int>, BoolVar> shifts; for (int n : all_nurses) { for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); shifts[key] = cp_model.NewBoolVar().WithName( absl::StrFormat("shift_n%dd%ds%d", n, d, s)); } } } // Each shift is assigned to exactly one nurse in the schedule period. for (int d : all_days) { for (int s : all_shifts) { std::vector<BoolVar> nurses; for (int n : all_nurses) { auto key = std::make_tuple(n, d, s); nurses.push_back(shifts[key]); } cp_model.AddExactlyOne(nurses); } } // Each nurse works at most one shift per day. for (int n : all_nurses) { for (int d : all_days) { std::vector<BoolVar> work; for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); work.push_back(shifts[key]); } cp_model.AddAtMostOne(work); } } // Try to distribute the shifts evenly, so that each nurse works // min_shifts_per_nurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int min_shifts_per_nurse = (num_shifts * num_days) / num_nurses; int max_shifts_per_nurse; if ((num_shifts * num_days) % num_nurses == 0) { max_shifts_per_nurse = min_shifts_per_nurse; } else { max_shifts_per_nurse = min_shifts_per_nurse + 1; } for (int n : all_nurses) { LinearExpr num_worked_shifts; for (int d : all_days) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); num_worked_shifts += shifts[key]; } } cp_model.AddLessOrEqual(min_shifts_per_nurse, num_worked_shifts); cp_model.AddLessOrEqual(num_worked_shifts, max_shifts_per_nurse); } LinearExpr objective_expr; for (int n : all_nurses) { for (int d : all_days) { for (int s : all_shifts) { if (shift_requests[n][d][s] == 1) { auto key = std::make_tuple(n, d, s); objective_expr += shifts[key] * shift_requests[n][d][s]; } } } } cp_model.Maximize(objective_expr); const CpSolverResponse response = Solve(cp_model.Build()); if (response.status() == CpSolverStatus::OPTIMAL) { LOG(INFO) << "Solution:"; for (int d : all_days) { LOG(INFO) << "Day " << std::to_string(d); for (int n : all_nurses) { for (int s : all_shifts) { auto key = std::make_tuple(n, d, s); if (SolutionIntegerValue(response, shifts[key]) == 1) { if (shift_requests[n][d][s] == 1) { LOG(INFO) << " Nurse " << std::to_string(n) << " works shift " << std::to_string(s) << " (requested)."; } else { LOG(INFO) << " Nurse " << std::to_string(n) << " works shift " << std::to_string(s) << " (not requested)."; } } } } LOG(INFO) << ""; } LOG(INFO) << "Number of shift requests met = " << response.objective_value() << " (out of " << num_nurses * min_shifts_per_nurse << ")"; } else { LOG(INFO) << "No optimal solution found !"; } // Statistics. LOG(INFO) << "Statistics"; LOG(INFO) << CpSolverResponseStats(response); } } // namespace sat } // namespace operations_research int main() { operations_research::sat::ScheduleRequestsSat(); return EXIT_SUCCESS; }
Java
package com.google.ortools.sat.samples; import com.google.ortools.Loader; import com.google.ortools.sat.CpModel; import com.google.ortools.sat.CpSolver; import com.google.ortools.sat.CpSolverStatus; import com.google.ortools.sat.LinearExpr; import com.google.ortools.sat.LinearExprBuilder; import com.google.ortools.sat.Literal; import java.util.ArrayList; import java.util.List; import java.util.stream.IntStream; /** Nurses problem with schedule requests. */ public class ScheduleRequestsSat { public static void main(String[] args) { Loader.loadNativeLibraries(); final int numNurses = 5; final int numDays = 7; final int numShifts = 3; final int[] allNurses = IntStream.range(0, numNurses).toArray(); final int[] allDays = IntStream.range(0, numDays).toArray(); final int[] allShifts = IntStream.range(0, numShifts).toArray(); final int[][][] shiftRequests = new int[][][] { { {0, 0, 1}, {0, 0, 0}, {0, 0, 0}, {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 1}, }, { {0, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 1, 0}, {1, 0, 0}, {0, 0, 0}, {0, 0, 1}, }, { {0, 1, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, { {0, 0, 1}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 0, 0}, }, { {0, 0, 0}, {0, 0, 1}, {0, 1, 0}, {0, 0, 0}, {1, 0, 0}, {0, 1, 0}, {0, 0, 0}, }, }; // Creates the model. CpModel model = new CpModel(); // Creates shift variables. // shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. Literal[][][] shifts = new Literal[numNurses][numDays][numShifts]; for (int n : allNurses) { for (int d : allDays) { for (int s : allShifts) { shifts[n][d][s] = model.newBoolVar("shifts_n" + n + "d" + d + "s" + s); } } } // Each shift is assigned to exactly one nurse in the schedule period. for (int d : allDays) { for (int s : allShifts) { List<Literal> nurses = new ArrayList<>(); for (int n : allNurses) { nurses.add(shifts[n][d][s]); } model.addExactlyOne(nurses); } } // Each nurse works at most one shift per day. for (int n : allNurses) { for (int d : allDays) { List<Literal> work = new ArrayList<>(); for (int s : allShifts) { work.add(shifts[n][d][s]); } model.addAtMostOne(work); } } // Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } for (int n : allNurses) { LinearExprBuilder numShiftsWorked = LinearExpr.newBuilder(); for (int d : allDays) { for (int s : allShifts) { numShiftsWorked.add(shifts[n][d][s]); } } model.addLinearConstraint(numShiftsWorked, minShiftsPerNurse, maxShiftsPerNurse); } LinearExprBuilder obj = LinearExpr.newBuilder(); for (int n : allNurses) { for (int d : allDays) { for (int s : allShifts) { obj.addTerm(shifts[n][d][s], shiftRequests[n][d][s]); } } } model.maximize(obj); // Creates a solver and solves the model. CpSolver solver = new CpSolver(); CpSolverStatus status = solver.solve(model); if (status == CpSolverStatus.OPTIMAL || status == CpSolverStatus.FEASIBLE) { System.out.printf("Solution:%n"); for (int d : allDays) { System.out.printf("Day %d%n", d); for (int n : allNurses) { for (int s : allShifts) { if (solver.booleanValue(shifts[n][d][s])) { if (shiftRequests[n][d][s] == 1) { System.out.printf(" Nurse %d works shift %d (requested).%n", n, s); } else { System.out.printf(" Nurse %d works shift %d (not requested).%n", n, s); } } } } } System.out.printf("Number of shift requests met = %f (out of %d)%n", solver.objectiveValue(), numNurses * minShiftsPerNurse); } else { System.out.printf("No optimal solution found !"); } // Statistics. System.out.println("Statistics"); System.out.printf(" conflicts: %d%n", solver.numConflicts()); System.out.printf(" branches : %d%n", solver.numBranches()); System.out.printf(" wall time: %f s%n", solver.wallTime()); } private ScheduleRequestsSat() {} }
C#
using System; using System.Collections.Generic; using System.Linq; using Google.OrTools.Sat; public class ScheduleRequestsSat { public static void Main(String[] args) { const int numNurses = 5; const int numDays = 7; const int numShifts = 3; int[] allNurses = Enumerable.Range(0, numNurses).ToArray(); int[] allDays = Enumerable.Range(0, numDays).ToArray(); int[] allShifts = Enumerable.Range(0, numShifts).ToArray(); int[,,] shiftRequests = new int[,,] { { { 0, 0, 1 }, { 0, 0, 0 }, { 0, 0, 0 }, { 0, 0, 0 }, { 0, 0, 1 }, { 0, 1, 0 }, { 0, 0, 1 }, }, { { 0, 0, 0 }, { 0, 0, 0 }, { 0, 1, 0 }, { 0, 1, 0 }, { 1, 0, 0 }, { 0, 0, 0 }, { 0, 0, 1 }, }, { { 0, 1, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, }, { { 0, 0, 1 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 0, 0 }, }, { { 0, 0, 0 }, { 0, 0, 1 }, { 0, 1, 0 }, { 0, 0, 0 }, { 1, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 }, }, }; // Creates the model. CpModel model = new CpModel(); // Creates shift variables. // shifts[(n, d, s)]: nurse 'n' works shift 's' on day 'd'. Dictionary<Tuple<int, int, int>, IntVar> shifts = new Dictionary<Tuple<int, int, int>, IntVar>(); foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { shifts.Add(Tuple.Create(n, d, s), model.NewBoolVar($"shifts_n{n}d{d}s{s}")); } } } // Each shift is assigned to exactly one nurse in the schedule period. foreach (int d in allDays) { foreach (int s in allShifts) { IntVar[] x = new IntVar[numNurses]; foreach (int n in allNurses) { var key = Tuple.Create(n, d, s); x[n] = shifts[key]; } model.Add(LinearExpr.Sum(x) == 1); } } // Each nurse works at most one shift per day. foreach (int n in allNurses) { foreach (int d in allDays) { IntVar[] x = new IntVar[numShifts]; foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); x[s] = shifts[key]; } model.Add(LinearExpr.Sum(x) <= 1); } } // Try to distribute the shifts evenly, so that each nurse works // minShiftsPerNurse shifts. If this is not possible, because the total // number of shifts is not divisible by the number of nurses, some nurses will // be assigned one more shift. int minShiftsPerNurse = (numShifts * numDays) / numNurses; int maxShiftsPerNurse; if ((numShifts * numDays) % numNurses == 0) { maxShiftsPerNurse = minShiftsPerNurse; } else { maxShiftsPerNurse = minShiftsPerNurse + 1; } foreach (int n in allNurses) { IntVar[] numShiftsWorked = new IntVar[numDays * numShifts]; foreach (int d in allDays) { foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); numShiftsWorked[d * numShifts + s] = shifts[key]; } } model.AddLinearConstraint(LinearExpr.Sum(numShiftsWorked), minShiftsPerNurse, maxShiftsPerNurse); } IntVar[] flatShifts = new IntVar[numNurses * numDays * numShifts]; int[] flatShiftRequests = new int[numNurses * numDays * numShifts]; foreach (int n in allNurses) { foreach (int d in allDays) { foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); flatShifts[n * numDays * numShifts + d * numShifts + s] = shifts[key]; flatShiftRequests[n * numDays * numShifts + d * numShifts + s] = shiftRequests[n, d, s]; } } } model.Maximize(LinearExpr.WeightedSum(flatShifts, flatShiftRequests)); // Solve CpSolver solver = new CpSolver(); CpSolverStatus status = solver.Solve(model); Console.WriteLine($"Solve status: {status}"); if (status == CpSolverStatus.Optimal || status == CpSolverStatus.Feasible) { Console.WriteLine("Solution:"); foreach (int d in allDays) { Console.WriteLine($"Day {d}"); foreach (int n in allNurses) { bool isWorking = false; foreach (int s in allShifts) { var key = Tuple.Create(n, d, s); if (solver.Value(shifts[key]) == 1L) { if (shiftRequests[n, d, s] == 1) { Console.WriteLine($" Nurse {n} work shift {s} (requested)."); } else { Console.WriteLine($" Nurse {n} work shift {s} (not requested)."); } } } } } Console.WriteLine( $"Number of shift requests met = {solver.ObjectiveValue} (out of {numNurses * minShiftsPerNurse})."); } else { Console.WriteLine("No solution found."); } Console.WriteLine("Statistics"); Console.WriteLine($" conflicts: {solver.NumConflicts()}"); Console.WriteLine($" branches : {solver.NumBranches()}"); Console.WriteLine($" wall time: {solver.WallTime()}s"); } }