ee.Number.lte
Returns 1 if and only if the first value is less than or equal to the second.
| Usage | Returns |
|---|
Number.lte(right) | Number |
| Argument | Type | Details |
|---|
this: left | Number | The left-hand value. |
right | Number | The right-hand value. |
Examples
print('5 less than or equal to 10?', ee.Number(5).lte(ee.Number(10))); // 1
print('10 less than or equal to 5?', ee.Number(10).lte(ee.Number(5))); // 0
print('5 less than or equal to 5?', ee.Number(5).lte(ee.Number(5))); // 1
Python setup
See the
Python Environment page for information on the Python API and using
geemap for interactive development.
import ee
import geemap.core as geemap
print('5 less than or equal to 10?',
ee.Number(5).lte(ee.Number(10)).getInfo()) # 1
print('10 less than or equal to 5?',
ee.Number(10).lte(ee.Number(5)).getInfo()) # 0
print('5 less than or equal to 5?',
ee.Number(5).lte(ee.Number(5)).getInfo()) # 1
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Last updated 2023-12-06 UTC.
[null,null,["Last updated 2023-12-06 UTC."],[[["The `lte()` method compares two numbers and returns 1 if the first number (left) is less than or equal to the second number (right), otherwise it returns 0."],["This method is useful for conditional statements and filtering data based on numerical comparisons within the Earth Engine environment."],["Usage involves calling `lte(right)` on a Number object (left), providing the right-hand value for comparison as an argument."]]],["The `lte` function compares two numbers and returns a numerical result. It assesses if the left-hand value (`this`) is less than or equal to the right-hand value (`right`). It returns `1` if this condition is true and `0` if it is false. The function's usage is `Number.lte(right)`. Both input values must be numbers. For instance, 5 `lte` 10 returns 1, while 10 `lte` 5 returns 0.\n"]]